1. Probability and Chance, Fritz Mauthner's Studies of Improbability

GA 163/1915-08-23/p011 ·1915-08-23 · English MediumMedium alignmentSome paragraph re-numbering between this translation and the German original — the locus may slip by a paragraph or two.
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Now we can pursue the matter further and ask what the chance is of throwing two sixes if two dice are thrown. This can also be calculated. You will get one divided by thirty-six if you calculate as follows: Throwing a \(2\) with one dice, you can get anything from a \(1\) to a \(6\) with the second. Getting a \(2\) with the first throw, you can also get anything from a \(2\) to a \(6\) with the second, and so on, until you have counted thirty-six different possible throws. The probability of getting any particular outcome is thus \(1\) in \(3\)6, or \(\frac{1}{36}\). If you wanted to calculate probability with \(3\) dice, you would get \(\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6}\), or \(\frac{1}{216}\), a very unlikely event indeed. The probability gets smaller and smaller the more dice are involved. The more possibilities there are, the less probable is any particular outcome.

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Cite: GA 163/1915-08-23/p011 · edition English